Question

Salut! Am mevoie de acest exercitiu​

Answer 1

Răspuns:

Explicație pas cu pas:

a) x²/(x+1)+3x³/(x+1)²=[x²(x+1)+3x³]/(x+1)²=(x³+x²+3x³)/(x+1)²=(4x³+x²)/(x+1)²=

x²(4x+1)/(x+1)²       x∈R\{-1}

b) x/(x+6)-(x²-1)/(x²-36)=[x(x-6)-(x²-1)]/(x+6)(x-6)=(x²-6x-x²+1)/(x+6)(x-6)=

(1-6x)/(x+6)(x-6)   x∈R\{-6,6}

c) 3x²/(x+6)·(x²-36)/9x³=3x²·(x²-36)/(x+6)·9x³=(x+6)(x-6)/(x+6)·3x=(x-6)/3x

x∈R\{-6,0}

d) x²/(x+1):3x³/(x²+2x+1)= x²/(x+1)·(x²+2x+1)/3x³=x²·(x²+2x+1)/(x+1)·3x³=

(x²+2x+1)/(x+1)·3x=(x+1)²/(x+1)·3x=(x+1)/3x    x∈R\{-1,0}