Question

salut,am nevoie urgent, dau 100 de puncte ​

Answer 1

Răspuns:

vezi rezolvarea în poză

Answer 2

Explicație pas cu pas:

$|x| < 3 \implies - 3 < x < 3$

A = (-3; 3)

$|x| \leqslant 5 \implies - 5 \leqslant x \leqslant 5$

B = [-5; 5]

$|x + 1| < 10 \iff - 10 < x + 1 < 10 \\ - 11 < x < 9$

C = (-11; 9)

$|x - 1| \leqslant 7 \implies - 7 \leqslant x - 1 \leqslant 7 \\ - 6 \leqslant x \leqslant 8$

D = [-6; 8]

$|x| < 6 \implies - 6 < x < 6$

E = {-5; -4; -3; -2; -1; 0; 1; 2; 3; 4; 5}

$|x + 3| < 8 \iff - 8 < x + 3 < 8 \\ - 11 < x < 5$

F = {0; 1; 2; 3; 4}

$- 3 < \dfrac{x}{2} < 4 \iff - 6 < x < 8$

A = (-6; 8)

$- 1 < \dfrac{4x + 6}{2} < 9 \iff - 2 < 4x + 6 < 18 \\ - 8 < 4x < 12 \iff - 2 < x < 3$

B = (-2; 3)

$- 9 < \dfrac{5x + 12}{2} < 16 \iff - 18 < 5x + 12 < 32 \\ - 30 < 5x < 20 \iff - 6 < x < 4$

C = (-6; 4)

$- 2 \leqslant \dfrac{5x + 9}{8} < 3 \iff - 16 \leqslant 5x + 9 < 24 \\ - 25 \leqslant 5x < 15 \iff - 5 \leqslant x < 3$

D = [-5; 3)

$- 8 < \dfrac{7x + 12}{2} \leqslant 12 \\ - 16 < 7x + 12 \leqslant 24 \\ - 28 < 7x \leqslant 12 \\ - 4 < x \leqslant \dfrac{12}{7} = 1\dfrac{5}{7}$

E = {-3; -2; -1; 0; 1}