Question

Salut! Imi trebuieste urgent raspunsurile la intrebari. deoarece sint de la test! Va rog mult!
a) Fie ∠ABC si [OC - bisectoarea , m(∠AOC ) = 29°15', m(∠AOB) = ________
b) (3x+ ________)²=_______+_______+0.16y²
c) Fie ΔABC(desenul alaturat), m(∠A)=46°, m(∠C)=________
d) (6x-_______)(6x+_____)=______-49y²

Answer 1

OC bisectoare ABC, imparte in doua unghiuri egale, jumatate din ABC
$\angle{AOB}=\angle{AOC}=29grade 15 minute=\frac{\angle{ABC}}{2}$
b)$(3x+0.4y)^2=9x^{2}+2.4xy+0.16y^{2}$
c) ABC triunghi isoscel cu AB=AC, atunci $\angle{B}=\angle{C}$ toate unghiurile au suma 180 grade atunci:
$\angle{A)+\angle{B}+\angle{C}=180\Rightarrow 2\angle{C}=180-\angle{A}\Rightarrow \angle{C}=\frac{180-46}{2}=\frac{134}{2}=67$
d) $(6x-7y)(6x+7y)=36x^{2}-49y^{2}$