Question

Salut, ma puteti ajuta la problema 087...?

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

∫ 1/sinx dx = ∫ sinx / sin²x dx =

= ∫ sinx / (1-cos²x) dx =

= -∫ (cosx)' / (1-cos²x) dx =

= (-1/2)•ln|(cosx-1)/(cosx+1)| =

= (1/2)•ln|(cosx+1)/(cosx-1)|

=> I = (1/2)•ln(1) - (1/2)•ln(3)

=> I = (1/2)•ln(3)