Question

Salut!!Ma puteti va rog ajuta la mate?tot exercitiul 8?Va rog mult!!

Answer 1

a. (5x+3)/2 +(3x-3)/4=4 |·4
2(5x+3)+(3x-3)=16
10x+6+3x-3=16
13x=16-6+3
13x=13
x=1
S={1}
b. (3y-1)/4 -y=2 |·4
3y-1-4y=8
-y=8+1
-y=9
y=-9
S={-9}
c.(5y-2)/3 - (4y-3)/5=6 |·15
5(5y-2) -3(4y-3)=90
25y-10-12y+9=90
13y-1=90
13y=90+1
13y=91
y=7
S={7}
d. (5x-1)/7+(4x-3)/2-(3-2x)/2=6 |·14
2(5x-1)+7(4x-3)-7(3-2x)=84
10x-2+28x-21-21+14x=84
52x-44=84
52x=84+44
52x=128
x=128/52
x=32/13
x=1 6/13