Question

Salut! Un mic ajutor la trigonometrie, va rog !!
Punctul 6 de la sub. I

Multumesc anticipat!

Answer 1

sin a =1/3

$sin^{2} a=\frac{1}{9}\\\\cos^{2} a=1-sin^{2} a=\frac{8}{9} \\cos a=\frac{2\sqrt{2} }{3} \\ctg a= \frac{cos a}{sin a} =\frac{2\sqrt{2} }{3} *3=2\sqrt{2}$