Question

Salutare, lume! Cer si eu Ajutor y=(x+3)^4+2

Dau COROANĂ

Answer 1

Răspuns:

(x+3)⁴+3=C₄⁰x⁴+C₄¹x³*3+C₄²x²*3²+C₄³x*3³+C₄⁴*3⁴+2

x⁴+4!/1!*3!*x³*3+4!/2!*2!*x²*9+4!/3!*x*27+81+2=

x⁴+4*x³+3*4/1*2*x²*9+4x*27+81+2=

x⁴+4x³+24x²*9+108x+83=

x⁴+4x³+216x²+108x+83

Explicație pas cu pas: