Question

Scoate factor comun, dupa model:a(x+1)+b(x+1)(a+b).
b) (x+2)(x-3)+4(x+2);
c) a(x+y)+b(x+y);
d) (x+3)2-(x+3);
e) (x-2)2-(x-2)3.​

Answer 1

Răspuns:

Explicație pas cu pas:

a(x+1)+b(x+1)(a+b)=(x+1)[a+b(a+b)]=(a+ab+b²)(x+1)

b) (x+2)(x-3)+4(x+2)=(x+2)(x-3+4)=(x+2)(x+1)

c) a(x+y)+b(x+y)=(x+y)(a+b)

d) (x+3)²-(x+3)=(x+3)(x+3-1)=(x+3)(x+2)

e) (x-2)²-(x-2)³=(x-2)²(1-x+2)=(x-2)²(3-x).