Question

scoate factorul comun:
a) 4a+8
b) 15b+10
c) 6b+4a
d) 3x+9y
e) 8a+6b
f) 3x+6y+9z

Answer 1

$a)4a + 8 = 4( \frac{4a}{4} + \frac{8}{4}) = 4(a + 2)$

$b)15b + 10 = 5( \frac{15b}{5} + \frac{10}{5}) = 5(3b + 2)$

$c)6b + 4a = 2( \frac{6b}{2} + \frac{4a}{2}) = 2(3b + 2a)$

$d)3x + 9y = 3( \frac{3x}{3} + \frac{9y}{3}) = 3(x + 3y)$

$e)8a + 6b = 2( \frac{8a}{2} + \frac{6b}{2}) = 2(4a + 3b)$

$f)3x + 6y + 9z = 3( \frac{3x}{3} + \frac{6y}{3} + \frac{9z}{3}) = 3(x + 2y + 3z)$