Question

Scoate factorul de sub radical:
a) √72
b)√48
c)√75
d)√90
e)$\frac{\sqrt{54} }{3}$
f)$5\sqrt \frac{1}{125}$
g)$\frac{1}{8} \sqrt{96}$
h)$\frac{1}{7} \sqrt{147}$
AJUTOR ÎMI TREBUIE URGENT!!!!! DAU COROANĂ!!!!!!!!!

Answer 1

a)

$\sqrt{75} = \sqrt{6 {}^{2} \times 2 } = 6 \sqrt{2}$

b)

$\sqrt{48} = \sqrt{4 {}^{2} \times 3 } = 4 \sqrt{3}$

c)

$\sqrt{75} = \sqrt{5 {}^{2} \times 3} = 5 \sqrt{3}$

d)

$\sqrt{90} = \sqrt{3 {}^{2} \times 10 } = 3 \sqrt{10}$

e)

$\frac{ \sqrt{54} }{ 3} = \frac{3 \sqrt{6} }{3} = \sqrt{6}$

f)

$5 \sqrt{ \frac{1}{125} } = 5 \times \frac{1}{ \sqrt{125} } = 5 \times \frac{1}{5 \sqrt{5} } = \frac{1}{ \sqrt{5} } = \frac{ \sqrt{5} }{5}$

g)

$\frac{1}{8} \sqrt{96} = \frac{1}{8} \sqrt{4 {}^{2} \times 6 } = \frac{1}{8} \sqrt{4 {}^{2} } \sqrt{6} = \frac{1}{8} 4 \sqrt{6} = \frac{1}{2} \sqrt{6} = \frac{ \sqrt{6} }{2}$

h)

$\frac{1}{7} \sqrt{147} = \frac{1}{7} \sqrt{7 {}^{2} \times 3} = \frac{1}{7} \sqrt{7 {}^{2} } \sqrt{3} = \frac{1}{7}7 \sqrt{3} = \sqrt{3}$