Question

scoate intregi din fractile urmatoare 15/8 21/11 49/6 38/11 63/22 135/21 235/4 85/7 493/2 5204/3 107/21
PS;Dau coroana

Answer 1

15/8  = 1 intreg si 7/8, deoarece 15 /8 = 8/8 + 7/8 = 1 intreg + 7/8

21/11 = 1 intreg si 10/11, deoarece 21/11 = 11/11 + 10/11

 49/6 = 8 intregi si 1/6 , ⇒ 48/6 + 1/6 = 8 intregi + 1/6

38/11 = 3 intregi si 5/11; ↔ 33/11 + 5/11 → de 3 ori 11/11=33/11

 63/22  = 2 intregi si 19/22→ 2 ×22/22 + 19/22

135/21 = 6 intregi si 9/21→ 135/21 - 6 × 21/21 = 135 /21 - 126/21 = 9/21 

 235/4 = 58 intregi si 3/5
→ pentru a afla intregii impart numaratorul la numitor
235 : 4 = 58 rest 3

85/7= 12 intregi si 1/7
85 : 7 = 12 rest 1

 493/2 = 246 intregi si 1/2
493: 2 =246 rest 1

5204/3 = 1 734 intregi si 2/3
5 204 : 3 = 1 734 rest 2

107/21= 5 intregi si 2/21
107 : 21 = 5 rest 2