Question

scoateti factori de sub radicali:

√17²·5
√2⁴·7³
√(-3)⁴·(-7)²·11
√2x²y⁶ (x,y,>0)
√9a²b(b>0)

AJUTOR URGENT!!! DAU CORONITA!!!

Answer 1

a)√17²·5=17√5
√2⁴·7³=2²·7√7=28√7
√(-3)⁴·(-7)²·11=(-3)²·7√11=63√11
√2x²y⁶=x·y³√2
√9a²b=3a√b

b)√(2/7)²·3/5=2/7√(3/5)
√(-3/4)²·13=3/4√13
√(2⁴·29/(-3)²·5²=2²√29/(3·5)=4√29/15
√(-5)²·7)/3⁴·2=5√7/(3²√2)=5√14/18
√a⁶b/c²=a³√b/c

c) -√225·7=-15√7
√28=2√7
√27=3√3
√700=10√7
√150=5√6
-√98=-7√2
√102=√(2·3·17) nu sunt termeni care ies de sub radical
√275=5√11
-√128=-8√2
√605=11√5
26 √80/169=26·4√5/13=8√5
-6 intreg √ 3 intreg 5/9 -aici nu inteleg ce-ai vrut sa scrii...
2/3 √3 3/20 - editat aiurea...... nu stiu ce e sub radical si ce nu
0,3 √300/7=0,3·10√3/√7=3√21/7
√13552=√(2⁴·7·11²)=2²·11√7=44√7
√25920=√(2⁶·5·9²)=2³·9√5=72√5