Question

Scoateti factorii de sub radical vreau doar rasp fara rezolvare
√72
√50
√48
√75
√27
√32
√12
√28
√24
√60
√245
√96
√80
√108

Answer 1

$\sqrt{72} = 6 \sqrt{2}$

$\sqrt{50} = 5 \sqrt{2}$

$\sqrt{48} = 4 \sqrt{3}$

$\sqrt{75} = 5 \sqrt{3}$

$\sqrt{27} = 3 \sqrt{3}$

$\sqrt{32} = 4 \sqrt{2}$

$\sqrt{12} = 2 \sqrt{3}$

$\sqrt{28} = 2 \sqrt{7}$

$\sqrt{24} = 2 \sqrt{6}$

$\sqrt{60} = 2 \sqrt{15}$

$\sqrt{245} = 7 \sqrt{5}$

$\sqrt{96} = 4 \sqrt{6}$

$\sqrt{80} = 4 \sqrt{5}$

$\sqrt{108} = 6 \sqrt{3}$

Answer 2

√72  =  √(36*2) = 6√2  ;
√50  =  √(25*2) = 5√2  ;
√48  =  √(16*3) = 4√3  ;
√75  =  √(25*3) = 5√3  ;
√27  =  √(9*3)   = 3√3  ;
√32  =  √(16*2) = 4√2  ;
√12  =  √(4*3)   = 2√2  ;
√28  =  √(4*7)   = 2√7  ;
√24  =  √(4*6)   = 2√6  ;
√60  =  √(4*15) = 2√15;
√245=  √(49*5) = 7√5  ;
√96  =  √(16*6) = 4√6  ;
√80  =   √(16*5)= 4√5  ;
√108=   √(36*3)= 6√3  ;