Question

Scoateți factorii de sub radicali:
a)
$\sqrt{96}$
$\sqrt{48}$
$\sqrt{72}$
$\sqrt{56}$
$\sqrt{84}$
$\sqrt{108}$
$\sqrt{162}$
$\sqrt{192}$
$\sqrt{150}$
$\sqrt{147}$
b)
$\sqrt{ {2}^{2} } \times {3}^{2} + 3 \sqrt{576}$
$\sqrt{ {2}^{3} } + 4 \sqrt{324}$

$\sqrt{ {2}^{4} } + 2 \sqrt{289}$

$\sqrt{ {6}^{2} } + 3 \sqrt{256}$
$\sqrt{33 + 6 \sqrt{361} }$

​

Answer 1

Răspuns:

Explicație pas cu pas:

a)

$\sqrt{96} = 4\sqrt{6} \\\sqrt{48} = 4\sqrt{3} \\\sqrt{72} = 6\sqrt{2} \\\sqrt{56} =2\sqrt{14} \\\sqrt{84} =2\sqrt{21}$$\sqrt{108} =6\sqrt{3} \\\sqrt{162} =9\sqrt{2} \\\sqrt{192} =8\sqrt{3} \\\sqrt{150} =5\sqrt{6}\\\sqrt{147} = 7\sqrt{3}$

b)

$2*9+3*24= 18+72= 90\\\\2\sqrt{2} +4*18= 2\sqrt{2} +72\\\\4+2*17= 4+34= 38\\\\6+3*16= 6+48=54\\\\\sqrt{33+6*19} =\sqrt{33+114} =\sqrt{147} =7\sqrt{3}$

Sper ca te-am ajutat!