Question

scoateti factorul de sub radical:
$\sqrt{72}$
$\sqrt{48}$
$\sqrt{75}$
$\sqrt{90}$
$\frac{ \sqrt{54} }{3}$

Answer 1

√72 = √36√2 = 6√2
√48 = √16√3 = 4√3
√75 = √25√3 = 5√3
√90 = √9√10 = 3√10
√54 /3 = √9√6 / 3 = 3√6 /3 = √6