Question

Scoateti factorul sub radical folosind
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Answer 1

a)

$\sqrt{ \frac{7}{9} } = \frac{ \sqrt{7} }{ \sqrt{9} } = \frac{ \sqrt{7} }{ \sqrt{ {3}^{2} } } = \frac{ \sqrt{7} }{3}$

b)

$\sqrt{ \frac{13}{8} } = \frac{ \sqrt{13} }{ \sqrt{8} } = \frac{ \sqrt{13} }{ \sqrt{ {2}^{3} } } = \frac{ \sqrt{13} }{2 \sqrt{2} }$

d)

$\sqrt{ \frac{ {2}^{5} }{ {3}^{4} } } = \frac{ \sqrt{ {2}^{5} } }{ \sqrt{ {3}^{4} } } = \frac{2 \times 2 \sqrt{2} }{3 \times 3} = \frac{4 \sqrt{2} }{9}$

e)

$\sqrt{ \frac{ {3}^{7} }{2 \times {5}^{3} } } = \frac{ \sqrt{ {3}^{7} } }{2 \times {5}^{3} } = \frac{3 \times 3 \times 3 \sqrt{3} }{5 \sqrt{2 \times 5} } = \frac{27 \sqrt{3} }{5 \sqrt{10} }$

h)

$\sqrt{ \frac{8}{3} } = \frac{ \sqrt{8} }{ \sqrt{3} } = \frac{ \sqrt{ {2}^{3} } }{ \sqrt{} 3} = \frac{2 \sqrt{2} }{ \sqrt{3} }$