Question

Scoateti intregii din fractiile
36 supra 11
220 supra 36
5214 supra 25

Answer 1

$\frac{36}{11}=\frac{33}{11}+\frac{3}{11}=3\frac{3}{11}$
$\frac{220}{36}=\frac{216}{36}+\frac{4}{36}=6\frac{1}{9}$
$\frac{5214}{25}=\frac{5200}{25}+\frac{14}{25}=208\frac{14}{25}$

Answer 2

36/11 = 3 intregi 3/11                   (( 3 x 11 + 3 ) / 11 = 36/11)
220/36 = 6 intregi 4/36                 ( (6 x 36 + 4)/36= 220/36)
5214/25 = 208 intregi 14/25         (( 208 x 25 +14)/25 = 5214/25)