Question

scrie in mai multe moduri un intreg ca suma a trei fractii cu numitorul:a)8;b)9;c)7;d)6

Answer 1

a) 8/8=2/8+1/8+5/8
b) 9/9=3/9+5/9+1/9
c) 7/7=1/7+3/7+3/7
d) 6/6=2/6+3/6+1/6

Answer 2

a)
$\frac{2}{8} + \frac{1}{8} + \frac{5}{8}=1 \\\\ \frac{7}{8} + \frac{1}{8} + \frac{0}{8}=1 \\\\ \frac{3}{8} + \frac{4}{8} + \frac{1}{8}=1 \\\\ \frac{1}{8} + \frac{1}{8} + \frac{6}{8}=1$

b)//
[tex] \frac{3}{9} + \frac{1}{9} + \frac{5}{9}=1 \\\\ \frac{7}{9} + \frac{2}{9} + \frac{0}{9}=1 \\\\ \frac{3}{9} + \frac{4}{9} + \frac{2}{9}=1 \\\\
 \frac{1}{9} + \frac{1}{9} + \frac{7}{9}=1 \\[/tex]

c)
[tex]
 \frac{4}{7} + \frac{1}{7} + \frac{2}{7}=1 \\\\ \frac{3}{7} + \frac{3}{7} + \frac{1}{7}=1 \\\\ \frac{2}{7} + \frac{3}{7} + \frac{2}{7}=1 \\\\ \frac{4}{7} + \frac{0}{7} + \frac{3}{7}=1 \\[/tex]

d)
[tex] \frac{2}{6} + \frac{1}{6} + \frac{3}{6}=1 \\\\ \frac{1}{6} + \frac{1}{6} + \frac{4}{6}=1 \\\\ \frac{5}{6} + \frac{1}{6} + \frac{0}{6}=1 \\\\ \frac{2}{6} + \frac{2}{6} + \frac{2}{6}=1 \\[/tex]