Question

scrie multimea divizorilor comuni ai nr si apoi precizeaza c.m.m.d.c. ai nr.:a)36 si 72;b)35si 45;c)30,36 si 54; d)40,60,120si 150
va rog pt coruana urgentt!

Answer 1

a) D36={1,2,3,4,9,12,18,36}
D72={1,2,3,4,8,9,18,24,36,72}

$36 = {2}^{2} \times {3}^{2}$
$72 = {2}^{3} \times {3}^{2}$
$c \: m \: m \: d \: c \: = {3}^{2} \times { 2 }^{2} = 9 \times 4 = 36$
b) D35={1,5,7,35}
D45={1,3,5,9,15,45}
$35 = 7 \times 5$
$45 = {3}^{2} \times 5$
$c \: m \: m \: d \: c \: = 5$
c) D30={1,2,3,5,6,10,15,30}
D36={1,2,3,4,9,12,18,36}
D54={1,2,3,6,9,18,27,54}

$30 = 2 \times 5 \times 3$
$36 = {2}^{2} \times {3}^{2}$
$54 = 2 \times {3}^{3}$
$c \: m \: m \: d \: c = 2 \times 3 = 16$

d) D40={1,2,4,5,8,10,20,40}
D60={1,2,3,4,5,6,10,12,15,20,30,60}
D120={1,2,3,4,6,20,30,40,60,130}
D150={1,2,3,5, continua tu te rog }

$40 = {2}^{3} \times 5$
$60 = {2 }^{2} \times 5 \times 3$
$120 = {2}^{3} \times 3 \times 5$
$150 = 2 \times {5 \times 3}^{2}$
$c \: m \: m \: d \: c \: = 2 \times 5 = 25$


Coroana pls !!