Question

scrie numerele naturale care au următoarele descompuneri:
4×10⁴+3×10³+0×10²+1×10¹+7×1
@×10⁵+0×10⁴+0×10³+0×10²+@×10¹+@×1​

Answer 1

Răspuns:

4×10⁴+3×10³+0×10²+1×10¹+7×1=43017

@×10⁵+0×10⁴+0×10³+0×10²+@×10¹+@×1​

unde a ≠ 0

a = 1 , 2 ,3 , 4 , 5 , 6 , 7 , 8 , 9

100011 , 200022 , 300033 , 400044 , 500055 , 600066 , 700077 ,  

800088 ,900099

Answer 2

Răspuns:

4 × 10⁴ + 3 × 10³ + 0 × 10² + 1 × 10¹ + 7 × 1 =

4 × 10 000 + 3 × 1 000 + 0 + 10 + 7 =

40 000 + 3 000 + 10 + 7 =

43 017

                                             

a × 10⁵ + 0 × 10⁴ + 0 × 10³ + 0 × 10² + a × 10¹ + a × 1 =

a × 100 000 + 0 + 0 + 0 + a × 10 + a =

a00 0aa