Question

scrie sub forma unei singure puteri cu exponent numarul natural
A) 2la puterea49:2la puterea13
B) 3la puterea103:3la puterea91
C) 5la puterea96:5la puterea96
D) 3la puterea42:3la puterea12:3
E) 7la puterea49:7la puterea15:7la puterea9
F) 7la puterea32:7la puterea
G) 5la puterea312:5la puterea56
H) 71la puterea32:71la puterea5
I)6la puterea112:6la puterea12:6la puterea43
J) 8la puterea91:8la puterea75:8la puterea10
Dau coroana ​

Answer 1

Răspuns:

Explicație pas cu pas:

a) 2⁴⁹:2¹³ = 2⁴⁹⁻¹³ = 2³⁶

b) 3¹⁰³:3⁹¹ = 3¹⁰³⁻⁹¹ = 3¹²

c) 5⁹⁶:5⁹⁶ = 5⁹⁶⁻⁹⁶ = 5⁰ = 1

d) 3⁴²:3¹²:3 = 3⁴²⁻¹²⁻¹ = 3²⁹

e) 7⁴⁹:7¹⁵:7⁹ = 7⁴⁹⁻¹⁵⁻⁹ = 7²⁵

f) 7³²:7ˣ = 7³²⁻ˣ

g) 5³¹²:5⁵⁶ = 5³¹²⁻⁵⁶ = 5²⁵⁶

h) 71³²:71⁵ = 71³²⁻⁵ = 71²⁷

i) 6¹¹²:6¹²:6⁴³ = 6¹¹²⁻¹²⁻⁴³=6⁵⁷

j) 8⁹¹:8⁷⁵:8¹⁰ = 8⁹¹⁻⁷⁵⁻¹⁰ = 8⁶