Question

scrie urmatoarele numere rationale ca patrate perfecte si apoi extrage radacina patrata
a) 121/1024
b) 625/361
c) 400/625
d) 324/1296
e) 2500/961​

Answer 1

Răspuns:

Explicație pas cu pas:

a) 121= 11²

1024=32²

121/1024= 11²/32²

b) 625= 25²

361= 19²

625/361= 25²/19²

c) 400= 20²

625= 25²

400/625= 20²/25²

d) 324= 18²

1296= 36²

324/1296= 18²/36²

e) 2500= 50²

961= 31²

2500/961= 50²/31²

Sper ca te-am ajutat!

Answer 2

Răspuns:

Explicație pas cu pas:

a)

$\frac{121}{1024} =\frac{11^2}{32^2} =(\frac{11}{32})^2\\\\\sqrt{\frac{121}{1024}} =\sqrt{(\frac{11}{32})^2}= \frac{11}{32}$

b)

$\frac{625}{621} =\frac{25 ^2}{19^2} =(\frac{25}{19})^2 \\\\\sqrt{\frac{625}{621}} = \sqrt{(\frac{25}{19})^2}=\frac{25}{19}$

c)

$\frac{400}{625} =\frac{25*16}{25*25}=\frac{16}{25}=\frac{4^2}{5^2} =(\frac{4}{5})^2\\\\\\\sqrt{\frac{400}{625}} =\sqrt{(\frac{4}{5})^2} = \frac{4}{5}$

d)

$\frac{324}{1296} =\frac{324}{4*324}=\frac{1}{4}=\frac{1}{2^2} =(\frac{1}{2})^2\\\\\sqrt{\frac{324}{1296}} =\sqrt{(\frac{1}{2})^2} = \frac{1}{2}$

e)

$\frac{2500}{961} =\frac{50^2}{31^2} =(\frac{50}{31})^2\\\\\sqrt{\frac{2500}{961}} =\sqrt{(\frac{50}{31})^2} = \frac{50}{31}$