Question

Scrierea ecuațiilor in forma ionica si ionica redus
1. ZnO+HCl
2. Zn(OH)2+H2SO4
3. CuSO4+NaOH
4. Al+HCl

Answer 1

Zn²⁺O²⁻+2H⁺Cl⁻---> Zn²⁺Cl⁻2 + H2O

2H⁺ + O²⁻---> H2O

Zn²⁺(OH)⁻2 +H⁺2SO4²⁻---> Zn²⁺SO4²⁻ + 2H2O

4H⁺ +2O²⁻---> 2H2O

Cu²⁺SO4²⁻ +2Na⁺OH⁻---> Na⁺2SO4²⁻ +Cu(OH)2↓

Cu²⁺+ 2OH⁻---> Cu(OH)2↓

2Al⁰ + 6H⁺Cl⁻---> 2Al³⁺Cl⁻3 + 3H⁰2↑

2Al⁰ +6H⁺---> 2Al³⁺ + 3H⁰2↑

Answer 2

1)ZnO+2HCl--->ZnCl2+H2O (ecuatie moleculara)

Zn²⁺ + O²⁻+2H⁺+2Cl⁻----->Zn²⁺+2Cl⁻+H2O (ecuatie ionica)

O²⁻+2H⁺---->H2O (ecuatie ionica completa

2)Zn(OH)2+H2SO4----->ZnSO4+2H2O (ecuatie moleculara)

Zn(OH)2+2H⁺+SO4²⁻--------->Zn²⁺+SO4²⁻+2H2O (ecuatie ionica)

Zn(OH)2+2H⁺---->Zn²⁺+2H2O (ecuatie ionica completa)

3)CuSO4+2NaOH---->Cu(OH)2+Na2SO4 (ecuatie moleculara)

Cu²⁺+SO4²⁻+2Na⁺+2OH⁻--->Cu(OH)2+2Na⁺+SO4²⁻ (ecuatie ionica)

Cu²⁺+2OH⁻----->Cu(OH)2 (ecuatie ionica completa)

4) 2Al+6HCl------>2AlCl3+3H2 (ecuatie moleculara)

2Al³⁺+6H⁺+6Cl⁻---->2Al³⁺+6Cl⁻+6H⁺ (ecuatie ionica)

Toate elementele s-au redus ecuatie ionica completa lipseste