Question

Scrieti 10 formule chimice(nu conteaza care)si aflatile 1.masa moleculara 2.raportul atomic 3.raportul de masa 4.compozitia procentuala

Answer 1

H2O - apă

MH2O = 2AH+AO=2*1+16=18g/mol

raport atomic => 2:1

raport de masa => 2g:16g=1g:8g

℅H=mH/M*100=2/18*100=Calculează..

℅O=mO/M*100=16/18*100=

HCl- acid clorhidric

MHCl=AH+ACl=1+35.5=36.5g/mol

raport atomic => 1:1

raport de masa => 1g:35.5g

℅H=1/36.5*100=
℅Cl=35.5/36.5*100=

NH3 - amoniac

MNH3=AN+3AH=14+3*1=17g/mol

raport atomic => 1:3

raport de masă => 14g:3g

℅N=14/17*100=
℅H=3/17*100=

NaOH - hidroxid de sodiu

MNaOH=ANa+AO+AH=23+16+1=40g/mol

raport atomic => 1:1:1

raport de masa => 23:16:1

℅Na=23/40*100=
℅O=16/40*100=
℅H=1/40*100=

H2SO4 - acid sulfuric

MH2SO4=98g/mol

raport atomic => 2:1:4

raport de masa => 2:32:64=1:16:32

℅H=2/98*100=
℅S=32/98*100=
℅O=64/98*100=


NaCl - clorură de sodiu

MNaCl=58.5g/mol

raport atomic => 1:1

raport de masa => 23:35.5

℅Na=23/58.5*100=
℅Cl=35.5/58.5*100=

H3PO4 - acid fosforic

MH3PO4=98g/mol

raport atomic => 3:1:4

raport de masă => 3:31:64

℅H=3/98*100=
℅P=31/98*100=
℅O=64/98*100=

CaO - oxid de calciu

MCaO=56g/mol

raport atomic => 1:1

raport de masa => 40:16=20:8=10:4=5:2

℅Ca=40/56*100=
℅O=16/56*100=

Al2(SO4)3 - sulfat de aluminiu

MAl2(SO4)3 = 2AAl+3(AS+4AO) = 2*27+3(32+4*16)=342g/mol

raport atomic => 2:3:12

raport de masa => 54:96:192=9:16:32

℅Al=54/342*100=
℅S=96/343*100=
℅O=192/342*100=

HBr - acid bromhidric

MHBr=81g/mol

raport atomic => 1:1

raport de masă => 1:80

℅H=1/81*100=
℅Br=80/81*100=