Question

scrieti ecuatia dreptei determinate de punctele A(2 3)si B(4 5)

Answer 1

[tex] \frac{x-xa}{xb-xa} = \frac{y-ya}{yb-ya} => \frac{x-2}{4-2} = \frac{y-3}{5-3} => \frac{x-2}{2} = \frac{y-3}{2} =>x-2=y-3 [/tex]
$x-y+1=0$