Question

Scrieti ecuatia tangentei la graficul functiei f in punctul A(2,5). f(x)= x^2+2/x

Answer 1

Răspuns:

Explicație pas cu pas: f(x)= $x^{2}$ + $\frac{2}{x}$

f'(x)=2x - $\frac{2}{x^{2} }$  

Ecuatia tangentei devine la Gf  : y-f(2)=f'(2)(x-2)

f(2)=5 ->>Ecuatia tangentei : y-5=$\frac{7}{2}$(x-2)

  y-5=$\frac{7}{2}$*x-7

$\frac{7}{2}$*x-y-2=0

f'(2)=4-$\frac{1}{2}$=$\frac{7}{2}$