Question

Scrieti ecuatile rectiilor transformarilor indicate in schema ..
P→P2O5→H3PO4→K3PO4→Zn3(PO4)2→ZnCl2←Zn

Answer 1

$P_{4} + 5O_{2} =\ \textgreater \[tex] P_{2}O_{5} P_{2}O_{5} + H_{2}O =\ \textgreater \ H_{3}PO_{4}$ [/tex]
$2H_{3}PO_{4}+3K_{2}CO_{3}=\ \textgreater \ K_{3}PO_{4}+3CO_{2} + H_{2}O$
$2 K_{3}PO_{4}+ZnI_2=\ \textgreater \ Zn_3(PO_4)_3+6KI$
$Zn_3(PO_4)_3+6HCl =\ \textgreater \ 3ZnCl_2 + 2 H_{3}PO_{4}$
$Zn+2HCl=\ \textgreater \ ZnCl_2 + H_2$