Question

Scrieti expresia_ sub forma de fractie algebrica ireductibila pe domeniul valorilor admisibile
Rezolvare:
____x-3__ - __x+3___ + __12x________=
       x+3          3-x               x la patrat-9

Answer 1

$\frac{x-3}{x+3}- \frac{x+3}{3-x} + \frac{12x}{ x^{2}-9} = \\ \frac{x-3}{x+3} + \frac{x+3}{x-3}+ \frac{12x}{ x^{2} -9}= \\ \frac{ x^{2} -6x+9+ x^{2} +6x+9+12x}{(x-3)(x+3)} = \\ \frac{2 x^{2} +12x+18}{(x-3)(x+3)} = \frac{2( x^{2}+6x+9)}{y(x-3)(x+3)} = \\ \frac{2 (x+3)^{2} }{(x-3)(x+3)} = \frac{2(x+3)}{x-3}$

Answer 2

Calculul formei cea mai simpla a expresiei alg.  ...