Question

scrieti partea intreaga si partea fractionara a numarului : a = 6,5^2:[5/8+(12,5-5)*2/5] -3,75-2,75
Va rog mult !

Answer 1

Calculam pe bucati ca sa fie clar:

6,5^2=(13/2)^2

[5/8+(12,5-5)*2/5]=[5/8+(7,5)*(2/5)]=5/8+(15/2)*(2/5)=5/8+3=29/8

-3,75-2,75=-6,5=-13/2

 6,5^2:[5/8+(12,5-5)*2/5] -3,75-2,75=

(13/2)^2 :(29/8) -13/2=

(13/2)^2 x8/29 -13/2= (factor comun 13/2)

(13/2)[(13/2) x8/29 -1]=

(13/2)[(13x4)/29 -1]=

(13/2)(52/29 -1)=

(13/2)(23/29)=

(13x23)/(2x29)=299/58

299/58=5,1551724138

[299/58]=5

{299/58}=0,1551724138

P.S. Sper sa nu fi gresit la calcule!