Question

scrieti patru numere naturale pentru care exista fractia:4supra x-3; 6 supra x ; 7 supra (x-2)(x+1) ; 10 supra x-4 ; 11 supra x+6

Answer 1

4/x-3 ∈N⇒X-3∈D₄=(1,2,4)
X-3=1⇒X=1+3⇒X=4
X-3=2⇒X=2+3⇒X=5
X-3=4⇒X=4+3⇒X=7
6/X⇒X∈D₆⇒X∈(1,2,3,6)
7/(X-2)(X+1)∈N⇒X∈D₇=(1,7)
(X-2)(X+1)=X²-X-2X-2=X²-3X-2
10/X-4∈N⇒X∈D10=(1,2,5,10)
X-4=1⇒X=4+1=5
X-4=5⇒X=4+5=9
X-4=2⇒X=4+2=6
X-4=10⇒X=4+10=14
11/X+6∈N⇒X∈D11=(1,11)
X+6=1⇒X=-5 NU ESTE SOLUTIE
X+6=11⇒X=11-5⇒X=6