Question

scrieti rezultatul sub forma unei singure puteri:
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RAPID
URGENT

Am nevoie de acest exercițiu mâine și nu îl înțeleg va rog să primesc răspunsuri bune ///

Mulțumesc!​

Answer 1

Răspuns:

Explicație pas cu pas:

a)

35/95 = 7/19

38/14 = 19/7

(7/19)^6 * (19/7)^6 = (7/19 *19/7)^6 = 1^6 = 1

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b)

(33/50)^9 * (25/22)^9 = (33/50 * 25/22)^9 = (3/2*1/2)^9 = (3/4)^9

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c)

(49/36)^2 = (7^2/6^2)^2 = (7/6)^4

(3/7)^4 * (7/6)^4 = (3/7 * 7/6)^4 = (1/2)^4 = 1/2^4

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d)

(7/17)^5 : (21/17)^5 = (7/17 : 21/17)^5 = (7/17 * 17/21)^5 = (1/3)^5 = 1/3^5

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e)

(13/8)^6 : (39/32)^6 = (13/8 : 39/32)^6 = (13/8 * 32/39)^6 = (4/3)^6

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f)

(25/6)^12 : (100/9)^6 = (25/6)^12 : (10/3)^12 = (25/6 : 10/3)^12

= (25/6 * 3/10)^12 = (75/60)^12 = (15/12)^12 = (5/4)^12

Answer 2

Răspuns:

a) 35/95=7/19 se simplifica si numaratorul si numitorul cu 5

38/14=19/7 se simplifica si numaratorul si numitorul cu 2

(7/19)⁶·(19/7)⁶=(7/19·19/7)⁶=1⁶=1

b) (33/50)⁹·(25/22)⁹=(33/50·25/22)⁹=(3/2·1/2)⁹=(3/4)⁹

c) (49/36)²=(7²/6²)²=(7/6)⁴

(3/7)⁴·(7/6)⁴=(3/7·7/6)⁴=(1/2)⁴=(1/2)⁴

d) (7/17)⁵:(21/17)⁵=(7/17:21/17)⁵=(7/17·17/21)⁵=(1/3)⁵=(1/3)⁵

e) (13/8)⁶:(39/32)⁶=(13/8:39/32)⁶=(13/8·32/39)⁶=(4/3)⁶

f) (25/6)¹²:(100/9)⁶= (25/6)¹²:(10/3)¹²=(25/6:10/3)¹²

= (25/6·3/10)¹²=(75/60)¹²=(15/12)¹²=(5/4)¹²