Question

scrieti sub forma algebrica numarul:
z=cos(pi/6 + i*sin pi/6 )

Answer 1

cos π/6 =√3/2

sin π/6 =1/2

z=cosπ/6 + i•sinπ/6

z=√3/2 + i/2

Daca ar fi z=2(cosπ/6 + i•sinπ/6),

atunci, z=2(√3/2 + i/2)

z=√3+i

(nu stiu de ce ai pus paranteza, am incercat sa-i gasesc un rost)