Question

scrieti sub forma de fractii ordinare ireductibile urmatoarele fractii zecimale:2,35;3,(3);0,3(6);2,(12)

Answer 1

Răspuns:

2,35= $\frac{235}{100}$= $\frac{47}{20}$  ( 47 nr prim)

3,(3)=$\frac{33-3}{9}$=$\frac{30}{9}$=$\frac{10}{3}$

0,3(6)= $\frac{36-3}{90}$=33/90= 11/3

2,(12)= $\frac{212-21}{99}$= $\frac{191}{99}$