Question

scrieti sub forma de nr ordinar numerele -1.6(3) si 2.(72)

Answer 1

-1,6(3)=-(163-16)/90=-147/90=-49/30

2,(75)=(275-2)/99=273/99=91/33

Answer 2

$-1,6(3)=-1 \frac{63-6}{90}=-1 \frac{57}{90}=- \frac{1*90+57}{90}= \frac{147}{90}= \frac{49}{30}$
$2,(72)=2 \frac{72}{99}=2 \frac{8}{11}= \frac{2*11+8}{11}= \frac{30}{11}$
sper ca te-am ajutat :)