Question

Scrieti sub formă de putere a unei fractii ordinare. va rog​

Answer 1

Răspuns:

g) (81/16)^5 : (6/4)^13 = (3/2)^20 : (6/4)^13 = (3/2)^20 : (3/2)^13 = (3/2)^7 = 2187/128

h) (3/5)^9 : 25/9 = 3^9/5^9 × 9/25 = 9×3^9/25×5^9 = 3^2×3^9/5^2×5^9 = 3^11/5^11