Question

scrieti sub forma de raport algebric ireductibil
$\frac{3a+2}{a- \sqrt{3} } : \frac{4+6a}{5 a^{2}-15 }$

Answer 1

$= \frac{3a+2}{a- \sqrt{3} }* \frac{5a^2-15}{2(2+3a)}= \frac{5a^2-15}{2(a- \sqrt{3}) }= \frac{( \sqrt{5}a- \sqrt{15})( \sqrt{5}a+ \sqrt{15}) }{2(a- \sqrt{3}) }=$$\frac{ \sqrt{5}(a- \sqrt{3})( \sqrt{5}a+ \sqrt{15}) }{2(a- \sqrt{3}) }= \frac{5(a+ \sqrt{3}) }{2}$