Question

SE AMESTECA 100 G SOL. CaCl2 cu C procentuala 30% cu 300 g sol CaCl2 cu C procentuala 10%,densitatea fiind 1,1g
se cere C%, Cm,Cn a sol finale

Answer 1

Răspuns:

c%=mdx100/ms      c,m=niu/V       c.n=echiv/V

c3%=md3x100/ms3   unde    md3=md1+md2      ms3=ms1+ms2=400g

md1= c1xms1/100=30g

md2= 30g

md3=60g

c3%= 60x100/400=>15%

niu=md3/M= 60g/111g/mol=0,54mol

Vs3= ms3x ro= 400gx1,1g/ml= 440ml-0,44 l

C,m=0,54/0,44mol/l=1,23M

E= M,sare/valenta metalului= 111/2->55,5 g/Eg

nr.echiv= m/E=60g/55,5g/Eg=1,08echivgram

c,n= 1,08/0,44=> 2,46 echivgram/l=2,46 N

Explicație: