Question

Se amesteca 400 ml de solutie H2SO4 de concentratie 2M(p=1,25 g/cm3) cu 200g solutie de H2SO4 de concentratie 94% si 50g H2SO4. Determinati concentratia procentuala de masa a solutiei obtinute.

Answer 1

Răspuns:

Explicație:

solutiaa finala , va avea concentratia

c3= (md1+md2+md)x100/(ms1+ms2+md)

ms1= roxv1= 1,25g/mlx400ml= 500g

ms2=200g

md=50gH2SO4

ms1+ms2+md= 500+200+50=>750g

c1=n1/v1----. >n1=2mol/lx0,4 l= 0,8molH2SO4

M,H2SO4=98g/mol------> m1=niuxM= 0,8X98g=78,4g

c2=md2x100/ms2---> md2= 94x200/100g= 188g

md3=78,4+188+50=> 316,4g

c3= 316,4x100/750=.....................calculeaza!!!!