Question

Se amesteca 500 ml de solutie de HCL de c 1=10%(p=1,049g/cm3) si c2=20%(p=1,142g/cm3).Concentratia solutiei finale va fi?

Answer 1

ro1=ms1/Vs1=>ms1=ro1*Vs1=1,049*500=524,5g HCl

C1=md1/ms1*100=>md1=10*524,5/100=52,45g HCl

ro2=ms2/Vs2=>ms2=1,142*500=571g HCl

C2=md2/ms2*100=>md2=20*571/100=114,2g HCl

mdf = 114,2+52,45=166,65g

msf = 571+524,5=1095,5g

Cfinal=mdf/msf*100=166,65/1095,5=Calculează!