Question

Se amesteca 800 grame de pulbere de sulf de puritate 90%,cu 200 grame de pulbere de puritate 60%.Sa se afle puritatea amestecului final ?

Answer 1

Răspuns:

m,impur 1= 800g

p1= 90%

m,impur2==200g

p2= 60%

p3=?

p3= (m,pur 1+ m,pur 2)x100/( m,impur1+m,impur2)

m,pur1= p1xm,impur1/100= 90x800/100g=720g

m,pur2= p2xm,impur 2/100= 200x60/100g=120g

p3= 840x100/1000=84%

Explicație: