Question

se amesteca 80cm3 solutie de h2so4 de concentratie 18% si niu = 1,13g/cm3 cu 120 cm3 solutie de h2so4 de concentratie 26% siniu = 1,19g/cm3. determinati concentratia procentuala si molara a solutiei finale

Answer 1

Vs₁=80cm³=0.08L
Cp₁=18%
ro₁=1,13g/cm³
Vs₂=120cm³=0.12L
Cp₂=26%
ro₂=1,19g/cm³

ro₁=ms1/Vs1==>ms₁=ro₁*Vs₁=1.13g/cm³×80cm³=90.4g

Cp₁=md1/ms1×100==>md₁=Cp₁×ms₁/100=16.272g

ro₂=ms₂/Vs₂==>ms₂=ro₂×Vs₂=1.19g/cm³×120cm³=142.8g

Cp₂=md₂/ms₂*100==>md₂=26×142.8/100=37.128g

mdf=md₁+md₂=16.272+37.128=53.4g
msf=ms₁+ms₂=90.4+142.8=233.2g
Vsf=Vs₁+Vs₂=80+120=200cm³=0.2L

Cpf=mdf/msf×100=53.4/233.2×100=22.898%

Cmf=mdf/M×Vsf=53.4/98×0.2=53.4/19.6=2.7244 moli/L