Question

Se amesteca o solutie de saramura cu masa de 450g si concentratia 62% cu o alta solutie de concentratie 80% si masa de sare dizolvata 25g. Peste solutia obtinuta se mai adauga 240g apa si 42g sare de puritate 82%. Calculati concentratia solutiei finale.
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Answer 1

Salut!

ms1=450g

c1=62%

md2=25g

c2=80%

adaugam 240g H2O

ms3=42g

c3=82%

c final=?

c1/100=md1/ms1

62/100=md1/450

md1=450*62/100=279

c2/100=md2/ms2

80/100=25/ms2

ms2=100*25/80=31.25

c3/100=md3/ms3

82/100=md3/42

md3=82*42/100=34.44

c final/100=md final/ms final

md final=md1+md2+md3=279+25+34.44=339.44

ms final=ms1+ms2+ms3+m h20=450+31.25+42+240=763.25

c final/100=339.44/523.25

c final=33944/763.25=44.47%

Sper ca te-am ajutat!