Question

Se ard complet 300kg de carbune de puritate 20%.
Ce cantitate de grame si moli de reactie se obtine?

Answer 1

C+O₂=CO₂
x=masa de carbon pur
x=300000g*20/100=60000g Carbon pur

Masa molara CO₂=12+2*16=44g
y=masa de CO₂ obtinuta
y=44*60000/12=220000g CO₂=220kg CO₂

1mol.........................44g
z moli.......................220000
z=220000*1/44=5000 moli CO₂=5 kmoli CO₂