Question

se arunca 2 zaruri. care este probbilitatea sa apara 2 nr. consecutive?

Answer 1

Număr cazuri posibile :

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

=>36 perechi

Număr cazuri favorabile :

(1,2),(2,3),(3,4),(4,5),(5,6)

=>5 perechi

$P = \frac{nr. \: cazuri \: favorabile}{nr. \: cazuri \: posibile} = \frac{5}{36}$