Question

se calculeaza 0,2×5 supra 7 + 11 supra 14
si B) ( - 43 +3²×2) : (-5²) + (17+15)×(-1)³​

Answer 1

0,2×5 supra 7 + 11 supra 14=

$\frac{2}{10} * \frac{5}{7} + \frac{11}{14} =\\\frac{1}{7} + \frac{11}{14}=\\\\\frac{2}{14} +\frac{11}{14} = \frac{13}{14} }$

 

( - 43 +3²×2) : (-5²) + (17+15)×(-1)³=

$(-43+9*2) :25 + 32*(-1)=\\(-43+18):25 -32=\\-25:25 -32=\\-1-32= -33$