Question

Se clorureaza fotochimic 50 moli la un randament al transf de 60%.Calculati masa de produs triclorurat obt.

Answer 1

CH4 + 3 Cl2 = CHCl3 + 3 HCl
randament = n practic/n teoretic * 100
n practic = 50*60/100 = 30 moli metan
M CHCl3 = 12+1+35,5*3 = 119,5 g/mol
1 mol metan.........119,5 g cloroform
30 moli metan..................x
x = 3585 g cloroform