Question

se considera a=5√12+3√27-9√3si b=√48+2√3-√75
calculati media lor geometrica

Answer 1

media geometrica este : mg=$\sqrt{a*b}$ 
a=5$\sqrt{12} +3 \sqrt{27} -9 \sqrt{3} =10\sqrt{3} +9 \sqrt{3} -9 \sqrt{3}=10 \sqrt{3}$
b=$\sqrt{48} +2 \sqrt{3} - \sqrt{75} = 4[tex] \sqrt{3} +2 \sqrt{3} - 5\sqrt{3} =[tex] \sqrt{3}$
mg=$\sqrt{} 10\sqrt{3} * \sqrt{3} = \sqrt{30}$