Question

se considera A,B,C si D trei puncte coliniare in aceasta ordine si punctele M SI N mijloacele segmentelor AB si respectiv BC Stiind ca ; a) AB =6 cm si BC = 4 cm determina lungim3a segmentelor AM,NC SI MN . b) AM =2 cm si MN =5 cm determina lungimea segmentelor AB,BC SI AC c) AN =6 cm si AC =10 Cm determina lungimea segmentelor NC ,BC SI AB
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Answer 1

a) AM=AB÷2=6cm÷2=3cm
NC=BC÷2=4cm÷2=2cm
MN=MB+BN=3cm+2cm=5cm
b)AB=AM×2=2cm×2=4cm
BN=5cm-2cm=3cm
BC=BN+NC=3cm+3cm=6cm
AC=AB+BC=4cm+6cm=10cm
c)NC=AC-AN=10cm-6cm=4cm
BC=BN congruent cu NC, deci BN=4cm
AB=AN-BN=6cm-4cm=2cm
Sper ca e bn:)