Question

Se consideră a =
${ \sqrt{5} }^{5} \div ( - \sqrt{5 {}^{3} } ) + 2 \times \sqrt{0.(3)} \times ( \frac{1}{ \sqrt{3} } ) {}^{ - 3}$
Sa se calculeze (a - 2 ) la puterea 2019.E URGENT!DAU COROANA!!
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Answer 1

$\it\ \sqrt5^5:(-\sqrt{5^3})=-\sqrt5^5:\sqrt5^3=-\sqrt5^{5-3}=-\sqrt5^2=-5\\ \\ 2\cdot\sqrt{0,(3)}\cdot\Big(\dfrac{1}{\sqrt3}\Big)^{-3}=2\sqrt{\dfrac{3}{9}}\cdot(\sqrt3)^3=2\dfrac{\sqrt3}{3}\cdot3\sqrt3=2\cdot3=6\\ \\ a=-5+6=1\\ \\ (a-2)^{2019}=(1-2)^{2019}=(-1)^{2019}=-1$