Question

Se considera ABCD-romb ,m (ABD)=75° iar AB=24cm.
Se cere :
a) aflati distanta de la A la BC
b) aflati aria rombului

Answer 1

a)m(∡ABD)=m(∡CBD)=75°=> m(∡ABE)=180-2x75=30°
m(∡ABE)=30°=>(Teorema ∡-lui de 30°)=>AE=12 cm
b) $A_{romb}$ =144x2=288